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  1. #1
    Join Date
    Dec 2011
    Posts
    235
    Scott plse post screen shot of the plan( the top view just line drawing sketch) if possible,since i dont have x5. But my bell shaped roof has a half circular periphery and concentric small semi circle on the peak. The center of both circles is exactly on the outer face of the wall. Basically when viewed from top it is two concentric circles whose centers is in the mid point of the line it coincides with the exterior face of the wall.it is known that the sum of the radial angles is =180 degree and the the shape of each individual roof planes is the same through out. as the radial angle gets near to zero the area is nearly the area of the trapizium. Therefore i can assure you the symbol i made out of this can give us any other equation other than circular top and equall division(the same area). I mean by stretching the x and y you can make it coincide the elliptical,hyperbolic, parabolic and any other practically useable mathematical equations having also varying z you can get the space object you may need. So then in the top view you can observe the changing shape(geomety and area) of the panels from the 90 degree to both sides(0 & 180 degree) gradually.
    Thanks
    Yusuf hassen/
    engineer & architect.......
    Win7 home premium,32bit,3GB ram ...
    X2/X4 premium
    Autocad 2010, Staadpro 2004.

  2. #2
    Join Date
    Dec 2005
    Location
    San Diego California
    Posts
    9,573
    Quote Originally Posted by yusuf View Post
    ..... Basically when viewed from top it is two concentric circles whose centers is in the mid point of the line it coincides with the exterior face of the wall. .....
    Wrong, the center of the bow window is different than that of the roof. Please build it to prove your point and post the plan.
    D. Scott Hall (The Bridge Troll)
    San Diego, Ca.
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